You can split up your scripts into files and "include" them with the source aka dot "." operator. The includes do not need to start with "#!/bin/bash", but they must either be in your PATH or have their PATH written exclusively in the main script.I was wondering whether there is an equivalent to the #include (used in c programs to import file content) in bash?
#!/bin/bash
# A script that includes another script
source My_Other_Script.sh # include is in $PATH
source /path/to/the/include/My_Other_Other_Script.sh # explicit PATHYou can always use . or source for that but just in case you also want a function that only loads a script once even though it's already been called many times in many co-scripts (something similar to use of Perl, require of Ruby and include_once of PHP, you can use Shell Script Loader. It's a carefully planned framework for shell scripts that provides a function named include(). This function can accept complete paths or partial paths that will be completed using search paths just like the concept of binaries with $PATH. If you want you may optionally use an available compiler to compile the scripts to merge them into single large file.I was wondering whether there is an equivalent to the #include (used in c programs to import file content) in bash? If an equivalent doesn't exist then anyone know a workaround?
