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Discussion Starter · #1 ·
I am trying to do following.

Start Up Tomcat

Tomcat can be started by executing the following commands:

$CATALINA_HOME\bin\startup.bat (Windows)

When I run above command on cmd prompt , I get message path can not be found. How to find path for $CATALINA_HOME from cmd prompt ?


Running this command on cmd prompt or starting tomcat service from "services" is same or different ?

thanks
 

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Discussion Starter · #3 ·
$CATALINA_HOME\bin\startup.bat - this is what I am typing at command prompt.
Tomcat is installed in the path "C:\apache-tomcat-5.5.27\bin"

thanks
 

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Try typing the following:
C:\apache-tomcat-5.5.27\bin\startup.bat

If your variables are correct, you should be able to start it with:
%CATALINA_HOME%\bin\startup.bat

I think...but I don't use Tomcat :smile:
 

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Discussion Starter · #5 ·
$CATALINA_HOME\bin\startup.bat - this is what I am typing at command prompt.
Tomcat is installed in the path "C:\apache-tomcat-5.5.27\bin"

thanks
 
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