#include in bash shell script

DJ_Dance · 08-26-2005, 05:23 AM

Hi,

I was wondering whether there is an equivalent to the #include (used in c programs to import file content) in bash? If an equivalent doesn't exist then anyone know a workaround?
I have various files with defined paths and commands which I want to hack onto my .bashrc file at different times. I know I can just copy the text over to the .bashrc every time I need it, but it seems like a really dumb way to go about it.

Thanks in advance.

k2t0f12d · 07-03-2007, 03:20 PM

Quote:

Originally Posted by DJ_Dance

I was wondering whether there is an equivalent to the #include (used in c programs to import file content) in bash?

You can split up your scripts into files and "include" them with the source aka dot "." operator. The includes do not need to start with "#!/bin/bash", but they must either be in your PATH or have their PATH written exclusively in the main script.

Code:

#!/bin/bash

# A script that includes another script

source My_Other_Script.sh    # include is in $PATH
source /path/to/the/include/My_Other_Other_Script.sh   # explicit PATH

08-26-2005, 05:23 AM	#1 (permalink)
DJ_Dance Registered User Join Date: Jul 2005 Posts: 24 OS: Windows XP	#include in bash shell script Hi, I was wondering whether there is an equivalent to the #include (used in c programs to import file content) in bash? If an equivalent doesn't exist then anyone know a workaround? I have various files with defined paths and commands which I want to hack onto my .bashrc file at different times. I know I can just copy the text over to the .bashrc every time I need it, but it seems like a really dumb way to go about it. Thanks in advance.