Welcome to Tech Support Forum home to more then 136,000 problems solved. Issues have included: Spyware, Malware, Virus Issues, Windows, Microsoft, Linux, Networking, Security, Hardware, and Gaming Getting your problem solved is as easy as:
1. Registering for a free account
2. Asking your question
3. Receiving an answer

Registered members:
* Get free support
* Communicate privately with other members (PM).
* Removal of this message
* See fewer ads.
* And much more..

 



Want to know how to post a question? click here Having problems with spyware and pop-ups? First Steps
Go Back   Tech Support Forum > The IT Pro > Certification & Career
User Name
Password
Site Map Register Donate Rules Blogs Mark Forums Read


Certification & Career A discussion forum for those of you getting started, or thinking about advancement.

Reply
 
LinkBack Thread Tools
Old 01-28-2009, 06:23 PM   #1 (permalink)
Registered User
 
Join Date: Jan 2009
Posts: 1
OS: Windows Vista SP 1


Subnetting Doubt

I am pretty confident of how to do the subnetting of any paticular class but what i am doubtful about is the concept, when you chose certain number of bits from the host portion in order to be used as subnet bits. Do we use the formula

2 to the power of "n" - 2 or do we use the formula 2 to the power of "n" .

As i have read it in a number of places that when we put in the 'ip subnet-zero' command on the router we can use the second formula instead of having a minus 2 in our formula but Cisco itself in the CCENT/CCNA ICND1 book says that we use the first formula in order to calculate the number of subnets..

Now can anyone confirm it whether we use the first formula or do we use the second formula when studying for the CCNA examination. Also if you have any link of the CISCO website that says so, it would be great..
vishal16 is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Reddit!
Reply With Quote
Important Information
Join the #1 Tech Support Forum Today - It's Totally Free!

TechSupportForum.com is a leading support website for your computer needs. We offer free, friendly and personalized computer support. Why pay to have your computer fixed when you can do it for free.

Join TechSupportforum.com Today - Click Here

Old 02-12-2009, 12:06 AM   #2 (permalink)
TSF Enthusiast
 
Join Date: Aug 2006
Posts: 949
OS: OS2 Warp


Re: Subnetting Doubt

from a ccna question

By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4 bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30. To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248. You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary?
* 10101100 00010000
* 00000010 10100000
* 10101100 00000000
* 11100000 11110000
Correct answer: A
bilbus is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Reddit!
Reply With Quote
Old 03-02-2009, 10:45 PM   #3 (permalink)
Registered User
 
Join Date: Mar 2009
Location: Terra
Posts: 2
OS: Windows 3.1


Re: Subnetting Doubt

You should understand why you're subtracting 2:
1. XXX.YYY.ZZZ.0 <----this will indicate network ID
2. XXX.YYY.ZZZ.255 <----broadcast address, it's not necessary to end with 255
13m4rc is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Reddit!
Reply With Quote
Reply


Thread Tools

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off




All times are GMT -7. The time now is 06:12 AM.



Copyright 2001 - 2009, Tech Support Forum
Home Tips Plus | Outdoor Basecamp | Automotive Support Forum

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85