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| Protocols and Routing IP, IPX and other protocol support |
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#1 (permalink) |
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Registered User
Join Date: Jul 2003
Location: New Zealand
Posts: 99
OS: Windows XP
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OSPF elections
Hi, i'm studying up on OSPF elections and would like something clarified
![]() I'm aware that any loopback address would take priority over a set IP address but have managed to confuse myself when it comes to elections taking place eg. Router 1 Loopback: 192.168.0.1 FastEthernet 0/0: 10.10.10.1 Serial 0/0: 172.16.0.1 Priority: 1 Router 2 No loopback FastEthernet 0/0: 10.10.10.2 Serial 0/0: 172.15.0.1 Priority: 1 It would be Router 1's loopback address (192.168.0.1) vs Router 2's Serial (172.15.0.1) and Router 1 becomming the DR because it's IP/RouterID is higher But what if this situation occured Router 1 Loopback: 10.1.1.1 FastEthernet 0/0: 10.10.10.1 Serial 0/0: 172.16.0.1 Priority: 1 Router 2 No loopback FastEthernet 0/0: 10.10.10.2 Serial 0/0: 172.20.0.1 Priority: 1 Where Router 2s serial address is higher than Router 1s loopback. Would Router 2 still become the DR in this case or would Router 1 still win because it's got a loopback? If someone could clarify this it would be appreciated
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#3 (permalink) |
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Registered User
Join Date: Nov 2009
Posts: 2
OS: windows xp, vista, 7; unix: ubuntu, backtrack
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Re: OSPF elections
Router 2 would win the election and become DR. The election process doesnt care how the router acquired its ID, it just cares which router has the higher ID.(lol just noticed the post date)
Last edited by TechnoBro; 11-08-2009 at 10:18 AM. |
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#4 (permalink) |
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Manager, Networking Forums
Join Date: Sep 2002
Location: S.E. Pennsylvania, US
Posts: 41,623
OS: Windows 7, XP-Pro, Vista, Linux
Blog Entries: 1
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Re: OSPF elections
Yep, this thread is past it's prime.
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