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#1 (permalink) |
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Registered User
Join Date: Jul 2008
Posts: 1
OS: Windows XP
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I've read an answer from one of your tech, and I would like to know why he is multiplying by 8 to know the correct answer? Here is a copy/paste from what he wrote...
"Now on to your 582 kbps download speeds. This may or may not be an issue depending on what exactly what you are refering to. If you are refering to the download task bar during a file transfer, this may be normal. Your download task bar should be expressed as 582 kB/sec, which is 582 kiloBytes per second, not kilobits per second. Multiply 582 kB by 8 to get 4656 kbps (kilo bit per second), which is actually 4.656 Mpbs (Megabits per second) which would be considered good cable modem performance." Is it because a 1 bit is equivalent to 8 octet? I would need to understand perfectly this math operation. And why would transfer rate no be expressed in term os real file size? Please help me, ![]() Sincerely |
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#2 (permalink) |
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Manager, Networking Forums
Join Date: Sep 2002
Location: S.E. Pennsylvania, US
Posts: 31,329
OS: XP-Pro, Vista, Linux
Blog Entries: 1
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Re: Troubling question
Broadband speeds are expressed in bits, however files are transferred in bytes.
One byte had 8 bits, hence the times 8 you are talking about. ![]()
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#3 (permalink) |
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TSF Enthusiast
Join Date: May 2008
Posts: 819
OS: XP Home SP2
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Re: Troubling question
1 byte = 8 bits
Download and transfer rates are measured in Mbps (megabits per second) Internet speeds are measured in MBps (megabytes per second) If you buy a 5mbit service, you can download at 625MB/s maximum. http://en.wikipedia.org/wiki/Binary_...e_than_one_bit |
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